02-13-2021, 11:05 PM RE: Serious Puzzles for The Research Folks Q
(This post was last modified: 02-13-2021, 11:57 PM by Max.)
Solving Section III
The following is 100% stolen from this site.
The key is 0362514 (KRYPTOS).
And the encryption process is Route Transposition followed by a Keyed Columnar Transposition.
Step 1, Route Transposition:
First we pad the message fitting it into a 86xN box.
Why padding it? To make the text in all the columns line up leaving columns of only two different lengths for the person decrypting to deal with, who is expected to know exactly how many of them there are and which ones they are. We are just being considerate of the guy with the key on the other end.
How many letters to add? The message length is 336 and we are fitting it into a box of width 86. 86 mod 7 = 2.
It means that every line except for the last one will have 2 extra columns. 336 mod 86 = 78.
The last line will be 78 letters long and 78 mod 7 = 1.
And since the number of the last line's "extra" columns has to be the same as the first lines to make the columns line up, we only need one extra Q to make it 2 for all the lines. Clear enough?
Now to the transposition itself:
In by Rows backwards into 86x4, Out by Columns in groups of 7 which is the length of the key:
SLOWLYDESPARATLYSLOWLYTHEREMAINSOFPASSAGEDEBRISTHATENCUM
BEREDTHELOWERPARTOFTHEDOORWAYWASREMOVEDWITHTREMBLINGHAND
SIMADEATINYBREACHINTHEUPPERLEFTHANDCORNERANDTHENWIDENING
THEHOLEALITTLEIINSERTEDTHECANDLEANDPEEREDINTHEHOTAIRESCA
PINGFROMTHECHAMBERCAUSEDTHEFLAMETOFLICKERBUTPRESENTLYDET
AILSOFTHEROOMWITHINEMERGEDFROMTHEMISTXCANYOUSEEANYTHINGQ?
->
?QGNIHTYNAEESUOYNACXTSIMEHTMORFDEGREMENIHTIWMOOREHTFOSLIATEDYLTNESERPTUBREKCILFOTEMALF
EHTDESUACREBMAHCEHTMORFGNIPACSERIATOHEHTNIDEREEPDNAELDNACEHTDETRESNIIELTTILAELOHEHTGNI
NEDIWNEHTDNARENROCDNAHTFELREPPUEHTNIHCAERBYNITAEDAMISDNAHGNILBMERTHTIWDEVOMERSAWYAWROO
DEHTFOTRAPREWOLEHTDEREBMUCNETAHTSIRBEDEGASSAPFOSNIAMEREHTYLWOLSYLTARAPSEDYLWOLS
What makes me think it was written backwards? Because the extra space is not at the end of the message but before the first letter. Who would bother calculating the position of the first letter and start writing the message beginning with the 7th column just to make it fill up the rectangle perfectly at the end?
I think it is easier to simply fill out the rectangle backwards if you are doing it with pen and paper.
Either way, it is 86x4 with 7 spaces in front of the first letter.
?QGNIHT YNAEESU OYNACXT SIMEHTM ORFDEGR EMENIHT IWMOORE HTFOSLI ATEDYLT NESERPT UBREKCI LFOTEMA LF
EHTDESU ACREBMA HCEHTMO RFGNIPA CSERIAT OHEHTNI DEREEPD NAELDNA CEHTDET RESNIIE LTTILAE LOHEHTG NI
NEDIWNE HTDNARE NROCDNA HTFELRE PPUEHTN IHCAERB YNITAED AMISDNA HGNILBM ERTHTIW DEVOMER SAWYAWR OO
DEHTFOT RAPREWO LEHTDER EBMUCNE TAHTSIR BEDEGAS SAPFOSN IAMEREH TYLWOLS YLTARAP SEDYLWO LS
Whichever way the text was written initially, after we restack it into 7 columns, it will result in:
?QGNIHT
EHTDESU
NEDIWNE
DEHTFOT
YNAEESU
ACREBMA
HTDNARE
RAPREWO
OYNACXT
HCEHTMO
NROCDNA
LEHTDER
SIMEHTM
RFGNIPA
HTFELRE
EBMUCNE
ORFDEGR
CSERIAT
PPUEHTN
TAHTSIR
EMENIHT
OHEHTNI
IHCAERB
BEDEGAS
IWMOORE
DEREEPD
YNITAED
SAPFOSN
HTFOSLI
NAELDNA
AMISDNA
IAMEREH
ATEDYLT
CEHTDET
HGNILBM
TYLWOLS
NESERPT
RESNIIE
ERTHTIW
YLTARAP
UBREKCI
LTTILAE
DEVOMER
SEDYLWO
LFOTEMA
LOHEHTG
SAWYAWR
LS
LF
NI
OO
Now write the key on top and proceed with...
Step 2, The Keyed Columnar Transposition:
KRYPTOS KOPRSTY
0362514 -> 0123456
?QGNIHT ?HNQTIG
EHTDESU ESDHUET
NEDIWNE NNIEEWD
DEHTFOT DOTETFH
YNAEESU YSENUEA
ACREBMA AMECABR
HTDNARE HRNTEAD
RAPREWO RWRAOEP
OYNACXT OXAYTCN
HCEHTMO HMHCOTE
NROCDNA NNCRADO
LEHTDER LETERDH
SIMEHTM STEIMHM
RFGNIPA RPNFAIG
HTFELRE HRETELF
EBMUCNE ENUBECM
ORFDEGR OGDRREF
CSERIAT CARSTIE
PPUEHTN PTEPNHU
TAHTSIR TITARSH
EMENIHT EHNMTIE
OHEHTNI ONHHITE
IHCAERB IRAHBEC
BEDEGAS BAEESGD
IWMOORE IROWEOM
DEREEPD DPEEDER
YNITAED YETNDAI
SAPFOSN SSFANOP
HTFOSLI HLOTISF
NAELDNA NNLAADE
AMISDNA ANSMADI
IAMEREH IEEAHRM
ATEDYLT ALDTTYE
CEHTDET CETETDH
HGNILBM HBIGMLN
TYLWOLS TLWYSOL
NESERPT NPEETRS
RESNIIE RINEEIS
ERTHTIW EIHRWTT
YLTARAP YAALPRT
UBREKCI UCEBIKR
LTTILAE LAITELT
DEVOMER DEOERMV
SEDYLWO SWYEOLD
LFOTEMA LMTFAEO
LOHEHTG LTEOGHH
SAWYAWR SWYARAW
LS L S
LF L F
NI N I
OO O O
Now to the last...
Step 3, Out by columns downwards, left to right resulting in:
?ENDYAHROHNLSRHEOCPTEOIBIDYSHNAIACHTNREYULDSLLSLLNO
HSNOSMRWXMNETPRNGATIHNRARPESLNNELEBLPIIACAEWMTW
NDITEENRAHCTENEUDRETNHAEOETFOLSEDTIWENHAEIOYTEY
QHEENCTAYCREIFTBRSPAMHHEWENATAMATEGYEERLBTEEFOASFIO
TUETUAEOTOARMAEERTNRTIBSEDDNIAAHTTMSTEWPIEROAGR
IEWFEBAECTDDHILCEIHSITEGOEAOSDDRYDLORITRKLMLEHA
GTDHARDPNEOHMGFMFEUHEECDMRIPFEIMEHNLSSTTRTVDOHW
Reminds you of anything? ;)
The decryption process requires knowing the key and the rectangle size for the route transposition:
KRYPTOS and 86.
First we determine the line lengths to split the message:
86 mod 7 = 2. It means that two of the columns are going to be longer.
Which two and by how much?
The first two in our system (they are 0 and 3 for the person decrypting the message), with lengths 51 and 47.
The difference between those lengths will be the same (4) for 86 mod 7 regardless of the message length.
You may want to find out why as an excercise.
So we...
Step 1, Split the input as follows:
0 ?ENDYAHROHNLSRHEOCPTEOIBIDYSHNAIACHTNREYULDSLLSLLNO
1 HSNOSMRWXMNETPRNGATIHNRARPESLNNELEBLPIIACAEWMTW
2 NDITEENRAHCTENEUDRETNHAEOETFOLSEDTIWENHAEIOYTEY
3 QHEENCTAYCREIFTBRSPAMHHEWENATAMATEGYEERLBTEEFOASFIO
4 TUETUAEOTOARMAEERTNRTIBSEDDNIAAHTTMSTEWPIEROAGR
5 IEWFEBAECTDDHILCEIHSITEGOEAOSDDRYDLORITRKLMLEHA
6 GTDHARDPNEOHMGFMFEUHEECDMRIPFEIMEHNLSSTTRTVDOHW
Step 2, Write it in columns... (i omitted it to make Step 3 clearer, hence the following text is on its side)
Step 3, Reorder the columns according to the key:
0 ?ENDYAHROHNLSRHEOCPTEOIBIDYSHNAIACHTNREYULDSLLSLLNO
3 QHEENCTAYCREIFTBRSPAMHHEWENATAMATEGYEERLBTEEFOASFIO
6 GTDHARDPNEOHMGFMFEUHEECDMRIPFEIMEHNLSSTTRTVDOHW
2 NDITEENRAHCTENEUDRETNHAEOETFOLSEDTIWENHAEIOYTEY
5 IEWFEBAECTDDHILCEIHSITEGOEAOSDDRYDLORITRKLMLEHA
1 HSNOSMRWXMNETPRNGATIHNRARPESLNNELEBLPIIACAEWMTW
4 TUETUAEOTOARMAEERTNRTIBSEDDNIAAHTTMSTEWPIEROAGR
Step 4, Chop them into 86-letter long lines
(in groups of 4 of course, since 337/86 is > 3 but is <= 4)
0 ?END YAHR OHNL SRHE OCPT EOIB IDYS HNAI ACHT NREY ULDS LLSL LNO
3 QHEE NCTA YCRE IFTB RSPA MHHE WENA TAMA TEGY EERL BTEE FOAS FIO
6 GTDH ARDP NEOH MGFM FEUH EECD MRIP FEIM EHNL SSTT RTVD OHW
2 NDIT EENR AHCT ENEU DRET NHAE OETF OLSE DTIW ENHA EIOY TEY
5 IEWF EBAE CTDD HILC EIHS ITEG OEAO SDDR YDLO RITR KLML EHA
1 HSNO SMRW XMNE TPRN GATI HNRA RPES LNNE LEBL PIIA CAEW MTW
4 TUET UAEO TOAR MAEE RTNR TIBS EDDN IAAH TTMS TEWP IERO AGR
Step 5, Read the resulting 4 lines of the message backwards (reverse of the Step 1 of encryption). Done.
If the same key KRYPTOS=0362514 was used to encrypt the 4th part, the decryption process would be as follows:
Let's say the number of columns for the route transposition was 49 or 21...
Step 1:
?OBKRUOXOGHULBSOLIFBBWFLRVQQPRNGKSSOTWTQSJQSSEKZZWATJKLUDIAWINFBNYPVTTMZFPKWGDKZXTJCDIGKUHUAUEKCAR
->
?OBKRUOXOGHULB
SOLIFBBWFLRVQQ
PRNGKSSOTWTQSJ
QSSEKZZWATJKLU
DIAWINFBNYPVTT
MZFPKWGDKZXTJC
DIGKUHUAUEKCAR
Step 2:
?SPQDMD
OORSIZI
BLNSAFG
KIGEWPK
RFKKIKU
UBSZNWH
OBSZFGU
XWOWBDA
OFTANKU
GLWTYZE
HRTJPXK
UVQKVTC
LQSLTJA
BQJUTCR
Step 3:
KOPRSTY KRYPTOS
0123456 -> 0362514
?SPQDMD ?QDPMSD
OORSIZI OSIRZOI
BLNSAFG BSGNFLA
KIGEWPK KEKGPIW
RFKKIKU RKUKKFI
UBSZNWH UZHSWBN
OBSZFGU OZUSGBF
XWOWBDA XWAODWB
OFTANKU OAUTKFN
GLWTYZE GTEWZLY
HRTJPXK HJKTXRP
UVQKVTC UKCQTVV
LQSLTJA LLASJQT
BQJUTCR BURJCQT
Step 4:
For 49 columns:
?QDPMSD BSGNFLA RKUKKFI OZUSGBF OAUTKFN HJKTXRP LLASJQT
OSIRZOI KEKGPIW UZHSWBN XWAODWB GTEWZLY UKCQTVV BURJCQT
For 21 columns:
?QDPMSD UZHSWBN HJKTXRP
OSIRZOI OZUSGBF UKCQTVV
BSGNFLA XWAODWB LLASJQT
KEKGPIW OAUTKFN BURJCQT
RKUKKFI GTEWZLY
Step 5:
For 49:
TQCJRUBVVTQCKUYLZWETGBWDOAWXNBWSHZUWIPGKEKIOZRISOTQJSALLPRXTKJHNFKTUAOFBGSUZOIFKKUKRALFNGSBDSMPDQ?
For 21:
YLZWETGIFKKUKRTQCJRUBNFKTUAOWIPGKEKTQJSALLBWDOAWXALFNGSBVVTQCKUFBGSUZOIOZRISOPRXTKJHNBWSHZUDSMPDQ?
Step 6: Breaking the cipher (most probably the same double-key Vigenere) and reading the message.
The final decrypted message
SLOWLYDESPARATLYSLOWLYTHEREMAINSOFPASSAGEDEBRIST
HATENCUMBEREDTHELOWERPARTOFTHEDOORWAYWASREMOVEDW
ITHTREMBLINGHANDSIMADEATINYBREACHINTHEUPPERLEFTH
ANDCORNERANDTHENWIDENINGTHEHOLEALITTLEIINSERTEDT
HECANDLEANDPEEREDINTHEHOTAIRESCAPINGFROMTHECHAMB
ERCAUSEDTHEFLAMETOFLICKERBUTPRESENTLYDETAILSOFTH
EROOMWITHINEMERGEDFROMTHEMISTXCANYOUSEEANYTHINGQ
Add in a sprinkling of punctuation, and it comes out to be
Slowly, desparatly slowly, the remains of passage debris that encumbered the lower
Part of the doorway was removed. With trembling hands i made a tiny breach in the upper
Lefthand corner and then widening the hole a little i inserted the candle and peered
in. The hot air escaping from the chamber caused the flame to flicker but presently
Details of the room within emerged from the mist x can you see anything q?
The above solution's came from the University of California, San Diego Math Dept.
https://www.math.ucsd.edu/
The following is 100% stolen from this site.
The key is 0362514 (KRYPTOS).
And the encryption process is Route Transposition followed by a Keyed Columnar Transposition.
Step 1, Route Transposition:
First we pad the message fitting it into a 86xN box.
Why padding it? To make the text in all the columns line up leaving columns of only two different lengths for the person decrypting to deal with, who is expected to know exactly how many of them there are and which ones they are. We are just being considerate of the guy with the key on the other end.
How many letters to add? The message length is 336 and we are fitting it into a box of width 86. 86 mod 7 = 2.
It means that every line except for the last one will have 2 extra columns. 336 mod 86 = 78.
The last line will be 78 letters long and 78 mod 7 = 1.
And since the number of the last line's "extra" columns has to be the same as the first lines to make the columns line up, we only need one extra Q to make it 2 for all the lines. Clear enough?
Now to the transposition itself:
In by Rows backwards into 86x4, Out by Columns in groups of 7 which is the length of the key:
SLOWLYDESPARATLYSLOWLYTHEREMAINSOFPASSAGEDEBRISTHATENCUM
BEREDTHELOWERPARTOFTHEDOORWAYWASREMOVEDWITHTREMBLINGHAND
SIMADEATINYBREACHINTHEUPPERLEFTHANDCORNERANDTHENWIDENING
THEHOLEALITTLEIINSERTEDTHECANDLEANDPEEREDINTHEHOTAIRESCA
PINGFROMTHECHAMBERCAUSEDTHEFLAMETOFLICKERBUTPRESENTLYDET
AILSOFTHEROOMWITHINEMERGEDFROMTHEMISTXCANYOUSEEANYTHINGQ?
->
?QGNIHTYNAEESUOYNACXTSIMEHTMORFDEGREMENIHTIWMOOREHTFOSLIATEDYLTNESERPTUBREKCILFOTEMALF
EHTDESUACREBMAHCEHTMORFGNIPACSERIATOHEHTNIDEREEPDNAELDNACEHTDETRESNIIELTTILAELOHEHTGNI
NEDIWNEHTDNARENROCDNAHTFELREPPUEHTNIHCAERBYNITAEDAMISDNAHGNILBMERTHTIWDEVOMERSAWYAWROO
DEHTFOTRAPREWOLEHTDEREBMUCNETAHTSIRBEDEGASSAPFOSNIAMEREHTYLWOLSYLTARAPSEDYLWOLS
What makes me think it was written backwards? Because the extra space is not at the end of the message but before the first letter. Who would bother calculating the position of the first letter and start writing the message beginning with the 7th column just to make it fill up the rectangle perfectly at the end?
I think it is easier to simply fill out the rectangle backwards if you are doing it with pen and paper.
Either way, it is 86x4 with 7 spaces in front of the first letter.
?QGNIHT YNAEESU OYNACXT SIMEHTM ORFDEGR EMENIHT IWMOORE HTFOSLI ATEDYLT NESERPT UBREKCI LFOTEMA LF
EHTDESU ACREBMA HCEHTMO RFGNIPA CSERIAT OHEHTNI DEREEPD NAELDNA CEHTDET RESNIIE LTTILAE LOHEHTG NI
NEDIWNE HTDNARE NROCDNA HTFELRE PPUEHTN IHCAERB YNITAED AMISDNA HGNILBM ERTHTIW DEVOMER SAWYAWR OO
DEHTFOT RAPREWO LEHTDER EBMUCNE TAHTSIR BEDEGAS SAPFOSN IAMEREH TYLWOLS YLTARAP SEDYLWO LS
Whichever way the text was written initially, after we restack it into 7 columns, it will result in:
?QGNIHT
EHTDESU
NEDIWNE
DEHTFOT
YNAEESU
ACREBMA
HTDNARE
RAPREWO
OYNACXT
HCEHTMO
NROCDNA
LEHTDER
SIMEHTM
RFGNIPA
HTFELRE
EBMUCNE
ORFDEGR
CSERIAT
PPUEHTN
TAHTSIR
EMENIHT
OHEHTNI
IHCAERB
BEDEGAS
IWMOORE
DEREEPD
YNITAED
SAPFOSN
HTFOSLI
NAELDNA
AMISDNA
IAMEREH
ATEDYLT
CEHTDET
HGNILBM
TYLWOLS
NESERPT
RESNIIE
ERTHTIW
YLTARAP
UBREKCI
LTTILAE
DEVOMER
SEDYLWO
LFOTEMA
LOHEHTG
SAWYAWR
LS
LF
NI
OO
Now write the key on top and proceed with...
Step 2, The Keyed Columnar Transposition:
KRYPTOS KOPRSTY
0362514 -> 0123456
?QGNIHT ?HNQTIG
EHTDESU ESDHUET
NEDIWNE NNIEEWD
DEHTFOT DOTETFH
YNAEESU YSENUEA
ACREBMA AMECABR
HTDNARE HRNTEAD
RAPREWO RWRAOEP
OYNACXT OXAYTCN
HCEHTMO HMHCOTE
NROCDNA NNCRADO
LEHTDER LETERDH
SIMEHTM STEIMHM
RFGNIPA RPNFAIG
HTFELRE HRETELF
EBMUCNE ENUBECM
ORFDEGR OGDRREF
CSERIAT CARSTIE
PPUEHTN PTEPNHU
TAHTSIR TITARSH
EMENIHT EHNMTIE
OHEHTNI ONHHITE
IHCAERB IRAHBEC
BEDEGAS BAEESGD
IWMOORE IROWEOM
DEREEPD DPEEDER
YNITAED YETNDAI
SAPFOSN SSFANOP
HTFOSLI HLOTISF
NAELDNA NNLAADE
AMISDNA ANSMADI
IAMEREH IEEAHRM
ATEDYLT ALDTTYE
CEHTDET CETETDH
HGNILBM HBIGMLN
TYLWOLS TLWYSOL
NESERPT NPEETRS
RESNIIE RINEEIS
ERTHTIW EIHRWTT
YLTARAP YAALPRT
UBREKCI UCEBIKR
LTTILAE LAITELT
DEVOMER DEOERMV
SEDYLWO SWYEOLD
LFOTEMA LMTFAEO
LOHEHTG LTEOGHH
SAWYAWR SWYARAW
LS L S
LF L F
NI N I
OO O O
Now to the last...
Step 3, Out by columns downwards, left to right resulting in:
?ENDYAHROHNLSRHEOCPTEOIBIDYSHNAIACHTNREYULDSLLSLLNO
HSNOSMRWXMNETPRNGATIHNRARPESLNNELEBLPIIACAEWMTW
NDITEENRAHCTENEUDRETNHAEOETFOLSEDTIWENHAEIOYTEY
QHEENCTAYCREIFTBRSPAMHHEWENATAMATEGYEERLBTEEFOASFIO
TUETUAEOTOARMAEERTNRTIBSEDDNIAAHTTMSTEWPIEROAGR
IEWFEBAECTDDHILCEIHSITEGOEAOSDDRYDLORITRKLMLEHA
GTDHARDPNEOHMGFMFEUHEECDMRIPFEIMEHNLSSTTRTVDOHW
Reminds you of anything? ;)
The decryption process requires knowing the key and the rectangle size for the route transposition:
KRYPTOS and 86.
First we determine the line lengths to split the message:
86 mod 7 = 2. It means that two of the columns are going to be longer.
Which two and by how much?
The first two in our system (they are 0 and 3 for the person decrypting the message), with lengths 51 and 47.
The difference between those lengths will be the same (4) for 86 mod 7 regardless of the message length.
You may want to find out why as an excercise.
So we...
Step 1, Split the input as follows:
0 ?ENDYAHROHNLSRHEOCPTEOIBIDYSHNAIACHTNREYULDSLLSLLNO
1 HSNOSMRWXMNETPRNGATIHNRARPESLNNELEBLPIIACAEWMTW
2 NDITEENRAHCTENEUDRETNHAEOETFOLSEDTIWENHAEIOYTEY
3 QHEENCTAYCREIFTBRSPAMHHEWENATAMATEGYEERLBTEEFOASFIO
4 TUETUAEOTOARMAEERTNRTIBSEDDNIAAHTTMSTEWPIEROAGR
5 IEWFEBAECTDDHILCEIHSITEGOEAOSDDRYDLORITRKLMLEHA
6 GTDHARDPNEOHMGFMFEUHEECDMRIPFEIMEHNLSSTTRTVDOHW
Step 2, Write it in columns... (i omitted it to make Step 3 clearer, hence the following text is on its side)
Step 3, Reorder the columns according to the key:
0 ?ENDYAHROHNLSRHEOCPTEOIBIDYSHNAIACHTNREYULDSLLSLLNO
3 QHEENCTAYCREIFTBRSPAMHHEWENATAMATEGYEERLBTEEFOASFIO
6 GTDHARDPNEOHMGFMFEUHEECDMRIPFEIMEHNLSSTTRTVDOHW
2 NDITEENRAHCTENEUDRETNHAEOETFOLSEDTIWENHAEIOYTEY
5 IEWFEBAECTDDHILCEIHSITEGOEAOSDDRYDLORITRKLMLEHA
1 HSNOSMRWXMNETPRNGATIHNRARPESLNNELEBLPIIACAEWMTW
4 TUETUAEOTOARMAEERTNRTIBSEDDNIAAHTTMSTEWPIEROAGR
Step 4, Chop them into 86-letter long lines
(in groups of 4 of course, since 337/86 is > 3 but is <= 4)
0 ?END YAHR OHNL SRHE OCPT EOIB IDYS HNAI ACHT NREY ULDS LLSL LNO
3 QHEE NCTA YCRE IFTB RSPA MHHE WENA TAMA TEGY EERL BTEE FOAS FIO
6 GTDH ARDP NEOH MGFM FEUH EECD MRIP FEIM EHNL SSTT RTVD OHW
2 NDIT EENR AHCT ENEU DRET NHAE OETF OLSE DTIW ENHA EIOY TEY
5 IEWF EBAE CTDD HILC EIHS ITEG OEAO SDDR YDLO RITR KLML EHA
1 HSNO SMRW XMNE TPRN GATI HNRA RPES LNNE LEBL PIIA CAEW MTW
4 TUET UAEO TOAR MAEE RTNR TIBS EDDN IAAH TTMS TEWP IERO AGR
Step 5, Read the resulting 4 lines of the message backwards (reverse of the Step 1 of encryption). Done.
If the same key KRYPTOS=0362514 was used to encrypt the 4th part, the decryption process would be as follows:
Let's say the number of columns for the route transposition was 49 or 21...
Step 1:
?OBKRUOXOGHULBSOLIFBBWFLRVQQPRNGKSSOTWTQSJQSSEKZZWATJKLUDIAWINFBNYPVTTMZFPKWGDKZXTJCDIGKUHUAUEKCAR
->
?OBKRUOXOGHULB
SOLIFBBWFLRVQQ
PRNGKSSOTWTQSJ
QSSEKZZWATJKLU
DIAWINFBNYPVTT
MZFPKWGDKZXTJC
DIGKUHUAUEKCAR
Step 2:
?SPQDMD
OORSIZI
BLNSAFG
KIGEWPK
RFKKIKU
UBSZNWH
OBSZFGU
XWOWBDA
OFTANKU
GLWTYZE
HRTJPXK
UVQKVTC
LQSLTJA
BQJUTCR
Step 3:
KOPRSTY KRYPTOS
0123456 -> 0362514
?SPQDMD ?QDPMSD
OORSIZI OSIRZOI
BLNSAFG BSGNFLA
KIGEWPK KEKGPIW
RFKKIKU RKUKKFI
UBSZNWH UZHSWBN
OBSZFGU OZUSGBF
XWOWBDA XWAODWB
OFTANKU OAUTKFN
GLWTYZE GTEWZLY
HRTJPXK HJKTXRP
UVQKVTC UKCQTVV
LQSLTJA LLASJQT
BQJUTCR BURJCQT
Step 4:
For 49 columns:
?QDPMSD BSGNFLA RKUKKFI OZUSGBF OAUTKFN HJKTXRP LLASJQT
OSIRZOI KEKGPIW UZHSWBN XWAODWB GTEWZLY UKCQTVV BURJCQT
For 21 columns:
?QDPMSD UZHSWBN HJKTXRP
OSIRZOI OZUSGBF UKCQTVV
BSGNFLA XWAODWB LLASJQT
KEKGPIW OAUTKFN BURJCQT
RKUKKFI GTEWZLY
Step 5:
For 49:
TQCJRUBVVTQCKUYLZWETGBWDOAWXNBWSHZUWIPGKEKIOZRISOTQJSALLPRXTKJHNFKTUAOFBGSUZOIFKKUKRALFNGSBDSMPDQ?
For 21:
YLZWETGIFKKUKRTQCJRUBNFKTUAOWIPGKEKTQJSALLBWDOAWXALFNGSBVVTQCKUFBGSUZOIOZRISOPRXTKJHNBWSHZUDSMPDQ?
Step 6: Breaking the cipher (most probably the same double-key Vigenere) and reading the message.
The final decrypted message
SLOWLYDESPARATLYSLOWLYTHEREMAINSOFPASSAGEDEBRIST
HATENCUMBEREDTHELOWERPARTOFTHEDOORWAYWASREMOVEDW
ITHTREMBLINGHANDSIMADEATINYBREACHINTHEUPPERLEFTH
ANDCORNERANDTHENWIDENINGTHEHOLEALITTLEIINSERTEDT
HECANDLEANDPEEREDINTHEHOTAIRESCAPINGFROMTHECHAMB
ERCAUSEDTHEFLAMETOFLICKERBUTPRESENTLYDETAILSOFTH
EROOMWITHINEMERGEDFROMTHEMISTXCANYOUSEEANYTHINGQ
Add in a sprinkling of punctuation, and it comes out to be
Slowly, desparatly slowly, the remains of passage debris that encumbered the lower
Part of the doorway was removed. With trembling hands i made a tiny breach in the upper
Lefthand corner and then widening the hole a little i inserted the candle and peered
in. The hot air escaping from the chamber caused the flame to flicker but presently
Details of the room within emerged from the mist x can you see anything q?
The above solution's came from the University of California, San Diego Math Dept.
https://www.math.ucsd.edu/
Half the population at Base Camp was clinically delusional.
-- John Krakauer 1996 Everest Expedition.
Apophenia is : “the tendency to perceive a connection or meaningful pattern between unrelated or random things (such as objects or ideas)”